-32y^2+72y+0=0

Solution for -32y^2+72y+0=0 equation:

-32y^2+72y+0=0

We add all the numbers together, and all the variables

-32y^2+72y=0

a = -32; b = 72; c = 0;
Δ = b2-4ac
Δ = 722-4·(-32)·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72}{2*-32}=\frac{-144}{-64}
=2+1/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72}{2*-32}=\frac{0}{-64}
=0
$